Problem: The numerator of a fraction is 6x+1, the denominator is 7−4x, and x can have any value between −2 and 2, both included. The values of x for which the numerator is greater than the denominator are:
Answer Choices:
A. 3/5<x≤2
B. 3/5≤x≤2
C. 0<x≤2
D. 0≤x≤2
E. −2≤x≤2
Solution:
6x+1>7−4x
x>3/5
3/5<x≤2