Problem: The altitude drawn to the base of an isosceles triangle is 8, and the perimeter is 32. The area of the triangle is:
Answer Choices:
A. 56
B. 48
C. 40
D. 32
E. 24
Solution:
Let base be 2b2a+2b=32;a+b=16
a2−b2=(a−b)(a+b)=64
a−b=4
a+b=16
b=6
area =8â‹…6=48