Problem: The first three terms of a geometric progression are 2,32,62. The fourth term is:
Answer Choices:
A. 1
B. 72
C. 82
D. 92
E. 102
Solution:
1=arn−1,r=32÷2∴ the 4th term is 2(232)3=222⋅2=1
or
Since 2,32,62 can be written as 23/6,22/6,21/6, the fourth term is 2∘=1.