Problem: The number of solutions in positive integers of is:
Answer Choices:
A.
B.
C.
D.
E.
Solution:
Solving for , we have . Since is a positive integer, must be a positive even number, so that must be a positive odd integer, such that . There are multiples of less than , half of which are even multiples and half, odd multiples. Therefore, there are possible solutions to the given equation under the stated conditions.