Problem:P is a point interior to rectangle ABCD and such that PA=3 inches, PD=4 inches, and PC=5 inches. Then PB, in inches, equals:
Answer Choices:
A. 23​
B. 32​
C. 33​
D. 42​
E. 2
Solution:
16−c2=9−d2
25−c2=x2−d2∴x2−9=9∴x=32​
or
Since x depends only upon the position of P, we may consider the special case where P is on side DA. We then have x^{2}-9=5^{2}-4^{2}, x^{2}=18, x=3 \sqrt
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