Problem: The sum of the reciprocals of the roots of the equation ax2+bx+c=0 is:
Answer Choices:
A. a1​+b1​
B. −bc​
C. cb​
D. −ba​
E. −cb​
Solution:
Let the roots be r and s; then r+s=−b/a and rs=c/a
∴r1​+s1​=rsr+s​=c/a−b/a​=−b/c,cî€ =0,aî€ =0