Problem: If r1​ and r2​ are the distinct real roots of x2+px+8=0; then it must follow that:
Answer Choices:
A. ∣r1​+r2​∣>42​
B. ∣r1​∣>3 or ∣r2​∣>3
C. ∣r1​∣>2 and ∣r2​∣>2
D. r1​<0 and r2​<0
E. ∣r1​+r2​∣<42​
Solution:
Since r1​ and r2​ are real and distinct, p2−32>0∴∣p∣>42​. But r1​+r2​=−p ∴∣r1​+r2​∣=∣p∣∴∣r1​+r2​∣>42​.