Problem: The equation 22x−8⋅2x+12=0 is satisfied by:
Answer Choices:
A. log3
B. 21log6
C. 1+log23
D. 1+log2log3
E. None of these
Solution:
22x−8⋅2x+12=(2x−6)(2x−2)=0∴2x−6=0,2x=6.
∴xlog2=log6=log2+log3∴x=1+log2log3.
Comment. The equation is also satisfied by x=1.