Problem: Triangle ABC is inscribed in a circle. The measures of the nonoverlapping minor arcsAB,BC, and CA are, respectively, x+75∘, 2x+25∘,3x−22∘. Then one interior angle of the triangle, in degrees, is:
Answer Choices:
A. 5721
B. 59
C. 60
D. 61
E. 122
Solution:
x+75+2x+25+3x−22=360∴x=47,AB=122∘;BC=119∘,CA=119∘. The interior angles of △ABC are, in degrees, 61,5921,5921.