Problem: Find the area of the smallest region bounded by the graphs of y=∣x∣ and x2+y2=4.
Answer Choices:
A. 4π​
B. 43π​
C. π
D. 23π​
E. 2Ï€
Solution:
The area of the smallest region bounded by y=∣x∣ and x2+ y2=4 is shown in the adjoining figure. Its areat is
41​(π22)=π