Problem:
If AB and CD are perpendicular diameters of circle Q, and ∠QPC=60∘, then the length of PQ divided by the length of AQ is
Answer Choices:
A. 23​​
B. 33​​
C. 22​​
D. 21​
E. 32​
Solution:
Triangle PQC is a 30∘−60∘−90∘ right triangle. Since AQ=CQ
AQPQ​=CQPQ​=3​1​=33​​.