Problem:
In the figure, ABCD is an isosceles trapezoid with side lengths AD=BC=5, AB=4, and DC=10. The point C is on DF and B is the midpoint of hypotenuse DE in the right triangle DEF. Then CF=
Answer Choices:
A. 3.25
B. 3.5
C. 3.75
D. 4.0
E. 4.25
Solution:
Drop perpendiculars AG and BH to DF. Then GH=4 and DG=HC=3. Since BH∥EF and DB=BE,DH=HF=7. Thus CF=HF−HC=7−3=4.
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