Problem:
Let ABCD be a parallelogram with ∠ABC= 120∘,AB=16 and BC=10. Extend CD through D to E so that DE=4. If BˉEˉ intersects AD at F, then FD is closest to
Answer Choices:
A. 1
B. 2
C. 3
D. 4
E. 5
Solution:
Since AD∥BC,△FDE is similar to △BCE. Hence
BCFD​=CEDE​ or FD=CEDE​⋅BC=4+164​⋅10=2
Note. The answer is independent of ∠ABC.