Problem:
If for any three distinct numbers a,b and c we define a,b,c​ by
a,b,c​=c−bc+a​,
then 1,−2,−3​=
Answer Choices:
A. −2
B. −52​
C. −41​
D. 52​
E. 2
Solution:
If a=1,b=−2 and c=−3, then a,b,c​=c−bc+a​=−3+2−3+1​=−1−2​=2.