Problem: ∣3−π∣=|3-\pi|=∣3−π∣=
Answer Choices:
A. 17\dfrac{1}{7}71​
B. 0.140.140.14
C. 3−π3-\pi3−π
D. 3+Ï€3+\pi3+Ï€
E. π−3\pi-3π−3
Solution:
Since 3−π<03-\pi<03−π<0, we have ∣3−π∣=−(3−π)=π−3|3-\pi|=-(3-\pi)=\pi-3∣3−π∣=−(3−π)=π−3.