Problem:
Each square in a 3×3 grid of squares is colored red, white, blue, or green so that every 2×2 square contains one square of each color. One such coloring is shown on the right below. How many different colorings are possible?
Answer Choices:
A. 24
B. 48
C. 60
D. 72
E. 96
Solution:
Label the squares as shown.
adg​beh​cfi​​
There are four 2×2 squares that need to satisfy the condition: abde, bcef, degh, and ef hi.
- Square abde : There are 4!=24 ways to color these squares using all four colors.
- Square bcef : Since squares b and e have already been colored, either c receives the same color as a and f receives the same color as d, or these are switched. This gives 2 choices at this stage. Using the numbers 1,2,3, and 4 to represent the colors, the two possibilities are pictured below.
13​24​13​​
13​24​31​​
- Remaining squares on the bottom row: Squares d and e have already been colored. If a and c have the same color, then there are two ways to color the three remaining squares:
131​242​131​​
132​241​132​​
On the other hand, if squares a and c receive different colors, then there is only one way to color the bottom row:
131​242​313​​
Thus the number of colorings is 24(2+1)=(D)72​.
The problems on this page are the property of the MAA's American Mathematics Competitions