Problem:
38+7845=\dfrac{\dfrac{3}{8}+\dfrac{7}{8}}{\dfrac{4}{5}}= 5483+87=
Answer Choices:
A. 111 B. 2516\dfrac{25}{16}1625 C. 222 D. 4320\dfrac{43}{20}2043 E. 4716\dfrac{47}{16}1647
Solution:
38+78=108=54\dfrac{3}{8}+\dfrac{7}{8}=\dfrac{10}{8}=\dfrac{5}{4}83+87=810=45. Therefore, 54÷45=54⋅54=2516\dfrac{5}{4} \div \dfrac{4}{5}=\dfrac{5}{4} \cdot \dfrac{5}{4}=\dfrac{25}{16}45÷54=45⋅45=1625.
Answer: B\boxed{B}B.
The problems on this page are the property of the MAA's American Mathematics Competitions