Problem:
The area of polygon ABCDEF is 52 with AB=8,BC=9 and FA=5. What is DE+EF?
Answer Choices:
A. 7
B. 8
C. 9
D. 10
E. 11
Solution:
Rectangle ABCG has area 8×9=72, so rectangle FEDG has area 72−52=20. The length of FG equals DE=9−5=4, so the length of EF is 420​=5. Therefore, DE+EF=4+5=9.
Answer: C​.
The problems on this page are the property of the MAA's American Mathematics Competitions
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