ΒΆ 1977 AHSME Problems and Solutions
Individual Problems and Solutions
For problems and detailed solutions to each of the 1977 AHSME problems, please refer below:
Problem 1: If y = 2 x y=2 xy = 2 x and z = 2 y z=2 yz = 2 y , then x + y + z x+y+zx + y + z equals
Answer Choices:
A. x xx
B. 3 x 3 x3 x
C. 5 x 5 x5 x
D. 7 x 7 x7 x
E. 9 x 9 x9 x
Solution:
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Problem 2: Which one of the following statements is false? All equilateral triangles are
Answer Choices:
A. equiangular
B. isosceles
C. regular polygons
D. congruent to each other
E. similar to each other
Solution:
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Problem 3: A man has $ 2.73 \$ 2.73$ 2 . 7 3 in pennies, nickels, dimes, quarters and half dollars. If he has an equal number of coins of each kind then the total number of coins he has is
Answer Choices:
A. 3 33
B. 5 55
C. 9 99
D. 10 101 0
E. 15 151 5
Solution:
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Problem 4: In triangle A B C , A B = A C A B C, A B=A CA B C , A B = A C and β A = 8 0 β \angle A=80^{\circ}β A = 8 0 β . If points D , E D, ED , E and F FF lie on sides B C B CB C , A C A CA C and A B A BA B , respectively, and C E = C D C E=C DC E = C D and B F = B D B F=B DB F = B D , then β E D F \angle E D Fβ E D F equals
Answer Choices:
A. 3 0 β 30^{\circ}3 0 β
B. 4 0 β 40^{\circ}4 0 β
C. 5 0 β 50^{\circ}5 0 β
D. 6 5 β 65^{\circ}6 5 β
E. none of these
Solution:
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Problem 5: The set of all points P PP such that the sum of the (undirected) distances from P PP to two fixed points A AA and B BB equals the distance between A AA and B BB is
Answer Choices:
A. the line segment from A AA to B BB
B. the line passing through A AA and B BB
C. the perpendicular bisector of the line segment from A AA to B BB
D. an ellipse having positive area
E. a parabola
Solution:
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Problem 6: If x , y x, yx , y and 2 x + y 2 2 x+\dfrac{y}{2}2 x + 2 y β are not zero, then ( 2 x + y 2 ) β 1 [ ( 2 x ) β 1 + ( y 2 ) β 1 ] \left(2 x+\dfrac{y}{2}\right)^{-1}\left[(2 x)^{-1}+\left(\dfrac{y}{2}\right)^{-1}\right]( 2 x + 2 y β ) β 1 [ ( 2 x ) β 1 + ( 2 y β ) β 1 ] equals
Answer Choices:
A. 1 11
B. x y β 1 x y^{-1}x y β 1
C. x β 1 y x^{-1} yx β 1 y
D. ( x y ) β 1 (x y)^{-1}( x y ) β 1
E. none of these
Solution:
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Problem 7: If t = 1 1 β 2 4 t=\dfrac{1}{1-\sqrt[4]{2}}t = 1 β 4 2 β 1 β , then t tt equals
Answer Choices:
A. ( 1 β 2 4 ) ( 2 β 2 ) (1-\sqrt[4]{2})(2-\sqrt{2})( 1 β 4 2 β ) ( 2 β 2 β )
B. ( 1 β 2 4 ) ( 1 + 2 ) (1-\sqrt[4]{2})(1+\sqrt{2})( 1 β 4 2 β ) ( 1 + 2 β )
C. ( 1 + 2 4 ) ( 1 β 2 ) (1+\sqrt[4]{2})(1-\sqrt{2})( 1 + 4 2 β ) ( 1 β 2 β )
D. ( 1 + 2 4 ) ( 1 + 2 ) (1+\sqrt[4]{2})(1+\sqrt{2})( 1 + 4 2 β ) ( 1 + 2 β )
E. β ( 1 + 2 4 ) ( 1 + 2 ) -(1+\sqrt[4]{2})(1+\sqrt{2})β ( 1 + 4 2 β ) ( 1 + 2 β )
Solution:
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Problem 8: For every triple ( a , b , c ) (a, b, c)( a , b , c ) of non-zero real numbers, form the number
a β£ a β£ + b β£ b β£ + c β£ c β£ + a b c β£ a b c β£ \dfrac{a}{|a|}+\dfrac{b}{|b|}+\dfrac{c}{|c|}+\dfrac{a b c}{|a b c|}
β£ a β£ a β + β£ b β£ b β + β£ c β£ c β + β£ a b c β£ a b c β
The set of all numbers formed is
Answer Choices:
A. { 0 } \{0\}{ 0 }
B. { β 4 , 0 , 4 } \{-4,0,4\}{ β 4 , 0 , 4 }
C. { β 4 , β 2 , 0 , 2 , 4 } \{-4,-2,0,2,4\}{ β 4 , β 2 , 0 , 2 , 4 }
D. { β 4 , β 2 , 2 , 4 } \{-4,-2,2,4\}{ β 4 , β 2 , 2 , 4 }
E. none of these
Solution:
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Problem 9: In the adjoining figure β E = 4 0 β \angle E=40^{\circ}β E = 4 0 β and arc β‘ A B , arc β‘ B C \operatorname{arc} A B, \operatorname{arc} B Ca r c A B , a r c B C and arc β‘ C D \operatorname{arc} C Da r c C D all have equal length. Find the measure of β A C D \angle A C Dβ A C D .
Answer Choices:
A. 1 0 β 10^{\circ}1 0 β
B. 1 5 β 15^{\circ}1 5 β
C. 2 0 β 20^{\circ}2 0 β
D. ( 45 2 ) β \left(\dfrac{45}{2}\right)^{\circ}( 2 4 5 β ) β
E. 3 0 β 30^{\circ}3 0 β
Solution:
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Problem 10: If ( 3 x β 1 ) 7 = a 7 x 7 + a 6 x 6 + β¦ + a 0 (3 x-1)^{7}=a_{7} x^{7}+a_{6} x^{6}+\ldots+a_{0}( 3 x β 1 ) 7 = a 7 β x 7 + a 6 β x 6 + β¦ + a 0 β , then a 7 + a 6 + β¦ + a 0 a_{7}+a_{6}+\ldots+a_{0}a 7 β + a 6 β + β¦ + a 0 β equals
Answer Choices:
A. 0 00
B. 1 11
C. 64 646 4
D. β 64 -64β 6 4
E. 128 1281 2 8
Solution:
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Problem 11: For each real number x xx , let [ x ] [x][ x ] be the largest integer not exceeding x xx (i.e., the integer n nn such that n β©½ x < n + 1 n \leqslant x<n+1n β©½ x < n + 1 ). Which of the following statements is (are) true?
I. [ x + 1 ] = [ x ] + 1 [x+1]=[x]+1[ x + 1 ] = [ x ] + 1 for all x xx
II. [ x + y ] = [ x ] + [ y ] [x+y]=[x]+[y][ x + y ] = [ x ] + [ y ] for all x xx and y yy
III. [ x y ] = [ x ] [ y ] [x y]=[x][y][ x y ] = [ x ] [ y ] for all x xx and y yy
Answer Choices:
A. none
B. I only
C. I and II only
D. III only
E. all
Solution:
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Problem 12: Al's age is 16 161 6 more than the sum of Bob's age and Carl's age, and the square of Al's age is 1632 16321 6 3 2 more than the square of the sum of Bob's age and Carl's age. The sum of the ages of Al, Bob and Carl is
Answer Choices:
A. 64 646 4
B. 94 949 4
C. 96 969 6
D. 102 1021 0 2
E. 140 1401 4 0
Solution:
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Problem 13: If a 1 , a 2 , a 3 , β¦ a_{1}, a_{2}, a_{3}, \ldotsa 1 β , a 2 β , a 3 β , β¦ is a sequence of positive numbers such that a n + 2 = a_{n+2}=a n + 2 β = a n a n + 1 a_{n} a_{n+1}a n β a n + 1 β for all positive integers n nn , then the sequence a 1 , a 2 , a 3 , β¦ a_{1}, a_{2}, a_{3}, \ldotsa 1 β , a 2 β , a 3 β , β¦ is a geometric progression
Answer Choices:
A. for all positive values of a 1 a_{1}a 1 β and a 2 a_{2}a 2 β
B. if and only if a 1 = a 2 a_{1}=a_{2}a 1 β = a 2 β
C. if and only if a 1 = 1 a_{1}=1a 1 β = 1
D. if and only if a 2 = 1 a_{2}=1a 2 β = 1
E. if and only if a 1 = a 2 = 1 a_{1}=a_{2}=1a 1 β = a 2 β = 1
Solution:
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Problem 14: How many pairs ( m , n ) (m, n)( m , n ) of integers satisfy the equation m + n = m n ? m+n=m n?m + n = m n ?
Answer Choices:
A. 1 11
B. 2 22
C. 3 33
D. 4 44
E. more than 4 44
Solution:
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Problem 15: Each of the three circles in the adjoining figure is externally tangent to the other two, and each side of the triangle is tangent to two of the circles. If each circle has radius three, then the perimeter of the triangle is
Answer Choices:
A. 36 + 9 2 36+9 \sqrt{2}3 6 + 9 2 β
B. 36 + 6 3 36+6 \sqrt{3}3 6 + 6 3 β
C. 36 + 9 3 36+9 \sqrt{3}3 6 + 9 3 β
D. 18 + 18 3 18+18 \sqrt{3}1 8 + 1 8 3 β
E. 45 454 5
Solution:
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Problem 16: If i 2 = β 1 i^{2}=-1i 2 = β 1 , then the sum cos β‘ 4 5 β + i cos β‘ 13 5 β + β¦ + i n cos β‘ ( 45 + 90 n ) β + \cos 45^{\circ}+i \cos 135^{\circ}+\ldots+i^{n} \cos (45+90 n)^{\circ}+cos 4 5 β + i cos 1 3 5 β + β¦ + i n cos ( 4 5 + 9 0 n ) β + β¦ + i 40 cos β‘ 364 5 β \ldots+i^{40} \cos 3645^{\circ}β¦ + i 4 0 cos 3 6 4 5 β equals
Answer Choices:
A. 2 2 \dfrac{\sqrt{2}}{2}2 2 β β
B. β 10 i 2 -10 i \sqrt{2}β 1 0 i 2 β
C. 21 2 2 \dfrac{21 \sqrt{2}}{2}2 2 1 2 β β
D. 2 2 ( 21 β 20 i ) \dfrac{\sqrt{2}}{2}(21-20 i)2 2 β β ( 2 1 β 2 0 i )
E. 2 2 ( 21 + 20 i ) \dfrac{\sqrt{2}}{2}(21+20 i)2 2 β β ( 2 1 + 2 0 i )
Solution:
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Problem 17: Three fair dice are tossed at random (i.e., all faces have the same probability of coming up). What is the probability that the three numbers turned up can be arranged to form an arithmetic progression with common difference one?
Answer Choices:
A. 1 6 \dfrac{1}{6}6 1 β
B. 1 9 \dfrac{1}{9}9 1 β
C. 1 27 \dfrac{1}{27}2 7 1 β
D. 1 54 \dfrac{1}{54}5 4 1 β
E. 7 36 \dfrac{7}{36}3 6 7 β
Solution:
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Problem 18: If y = ( 2 3 ) ( 3 4 ) β― ( n [ n + 1 ] ) β― ( 31 32 ) y=\left(\log _{2} 3\right)\left(\log _{3} 4\right) \cdots\left(\log _{n}[n+1]\right) \cdots\left(\log _{31} 32\right)y = ( log 2 β 3 ) ( log 3 β 4 ) β― ( log n β [ n + 1 ] ) β― ( log 3 1 β 3 2 ) then
Answer Choices:
A. 4 < y < 5 4<y<54 < y < 5
B. y = 5 y=5y = 5
C. y = 6 y=6y = 6
D. 6 < y < 7 6<y<76 < y < 7
E. none of these answers
Solution:
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Problem 19: Let E EE be the point of intersection of the diagonals of convex quadrilateral A B C D A B C DA B C D , and let P , Q , R P, Q, RP , Q , R and S SS be the centers of the circles circumscribing triangles A B E , B C E , C D E A B E, B C E, C D EA B E , B C E , C D E and A D E A D EA D E , respectively. Then
Answer Choices:
A. P Q R S P Q R SP Q R S is a parallelogram
B. P Q R S P Q R SP Q R S is a parallelogram if and only if A B C D A B C DA B C D is a rhombus
C. P Q R S P Q R SP Q R S is a parallelogram if and only if A B C D A B C DA B C D is a rectangle
D. P Q R S P Q R SP Q R S is a parallelogram if and only if A B C D A B C DA B C D is a parallelogram
E. none of the above are true
Solution:
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Problem 20: For how many paths consisting of a sequence of horizontal and/or vertical line segments, with each segment connecting a pair of adjacent letters in the diagram below, is the word C O N T E S T CONTESTC O N T E S T spelled out as the path is traversed from beginning to end?
C C
C
C O C COC
C O C
C O N O C CONOC
C O N O C
C O N T N O C CONTNOC
C O N T N O C
C O N T E T N O C CONTETNOC
C O N T E T N O C
C O N T E S E T N O C CONTESETNOC
C O N T E S E T N O C
C O N T E S T S E T N O C CONTESTSETNOC
C O N T E S T S E T N O C
Answer Choices:
A. 63 636 3
B. 128 1281 2 8
C. 129 1291 2 9
D. 255 2552 5 5
E. none of these answers
Solution:
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Problem 21: For how many values of the coefficient a aa do the equations
x 2 + a x + 1 = 0 x^{2}+a x+1=0
x 2 + a x + 1 = 0
and
x 2 β x β a = 0 x^{2}-x-a=0
x 2 β x β a = 0
have a common real solution?
Answer Choices:
A. 0 00
B. 1 11
C. 2 22
D. 3 33
E. infinitely many
Solution:
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Problem 22: If f ( x ) f(x)f ( x ) is a real valued function of the real variable x xx , and f ( x ) f(x)f ( x ) is not identically zero, and for all a aa and b bb ,
f ( a + b ) + f ( a β b ) = 2 f ( a ) + 2 f ( b ) , f(a+b)+f(a-b)=2 f(a)+2 f(b),
f ( a + b ) + f ( a β b ) = 2 f ( a ) + 2 f ( b ) ,
then for all x xx and y yy
Answer Choices:
A. f ( 0 ) = 1 f(0)=1f ( 0 ) = 1
B. f ( β x ) = β f ( x ) f(-x)=-f(x)f ( β x ) = β f ( x )
C. f ( β x ) = f ( x ) f(-x)=f(x)f ( β x ) = f ( x )
D. f ( x + y ) = f ( x ) + f ( y ) f(x+y)=f(x)+f(y)f ( x + y ) = f ( x ) + f ( y )
E. there is a positive number T TT such that f ( x + T ) = f ( x ) f(x+T)=f(x)f ( x + T ) = f ( x )
Solution:
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Problem 23: If the solutions of the equation x 2 + p x + q = 0 x^{2}+p x+q=0x 2 + p x + q = 0 are the cubes of the solutions of the equation x 2 + m x + n = 0 x^{2}+m x+n=0x 2 + m x + n = 0 , then
Answer Choices:
A. p = m 3 + 3 m n p=m^{3}+3 m np = m 3 + 3 m n
B. p = m 3 β 3 m n p=m^{3}-3 m np = m 3 β 3 m n
C. p + q = m 3 p+q=m^{3}p + q = m 3
D. ( m n ) 3 = p q \left(\dfrac{m}{n}\right)^{3}=\dfrac{p}{q}( n m β ) 3 = q p β
E. none of these answers
Solution:
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Problem 24: Find the sum
1 1 ( 3 ) + 1 3 ( 5 ) + β¦ + 1 ( 2 n β 1 ) ( 2 n + 1 ) + β¦ + 1 255 ( 257 ) \dfrac{1}{1(3)}+\dfrac{1}{3(5)}+\ldots+\dfrac{1}{(2 n-1)(2 n+1)}+\ldots+\dfrac{1}{255(257)}
1 ( 3 ) 1 β + 3 ( 5 ) 1 β + β¦ + ( 2 n β 1 ) ( 2 n + 1 ) 1 β + β¦ + 2 5 5 ( 2 5 7 ) 1 β
Answer Choices:
A. 127 255 \dfrac{127}{255}2 5 5 1 2 7 β
B. 128 255 \dfrac{128}{255}2 5 5 1 2 8 β
C. 1 2 \dfrac{1}{2}2 1 β
D. 128 257 \dfrac{128}{257}2 5 7 1 2 8 β
E. 129 257 \dfrac{129}{257}2 5 7 1 2 9 β
Solution:
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Problem 25: Determine the largest positive integer n nn such that 1005 ! 1005 !1 0 0 5 ! is divisible by 1 0 n 10^{n}1 0 n .
Answer Choices:
A. 102 1021 0 2
B. 112 1121 1 2
C. 249 2492 4 9
D. 502 5025 0 2
E. none of these answers
Solution:
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Problem 26: Let a , b , c a, b, ca , b , c and d dd be the lengths of sides M N , N P , P Q M N, N P, P QM N , N P , P Q and Q M Q MQ M , respectively, of quadrilateral M N P Q M N P QM N P Q . If A AA is the area of M N P Q M N P QM N P Q , then
Answer Choices:
A. A = ( a + c 2 ) ( b + d 2 ) A=\left(\dfrac{a+c}{2}\right)\left(\dfrac{b+d}{2}\right)A = ( 2 a + c β ) ( 2 b + d β ) if and only if M N P Q M N P QM N P Q is convex
B. A = ( a + c 2 ) ( b + d 2 ) A=\left(\dfrac{a+c}{2}\right)\left(\dfrac{b+d}{2}\right)A = ( 2 a + c β ) ( 2 b + d β ) if and only if M N P Q M N P QM N P Q is a rectangle
C. A β©½ ( a + c 2 ) ( b + d 2 ) A \leqslant\left(\dfrac{a+c}{2}\right)\left(\dfrac{b+d}{2}\right)A β©½ ( 2 a + c β ) ( 2 b + d β ) if and only if M N P Q M N P QM N P Q is a rectangle
D. A β©½ ( a + c 2 ) ( b + d 2 ) A \leqslant\left(\dfrac{a+c}{2}\right)\left(\dfrac{b+d}{2}\right)A β©½ ( 2 a + c β ) ( 2 b + d β ) if and only if M N P Q M N P QM N P Q is a parallelogram
E. A β©Ύ ( a + c 2 ) ( b + d 2 ) A \geqslant\left(\dfrac{a+c}{2}\right)\left(\dfrac{b+d}{2}\right)A β©Ύ ( 2 a + c β ) ( 2 b + d β ) if and only if M N P Q M N P QM N P Q is a parallelogram
Solution:
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Problem 27: There are two spherical balls of different sizes lying in two corners of a rectangular room, each touching two walls and the floor. If there is a point on each ball which is 5 55 inches from each wall which that ball touches and 10 101 0 inches from the floor, then the sum of the diameters of the balls is
Answer Choices:
A. 20 202 0 inches
B. 30 303 0 inches
C. 40 404 0 inches
D. 60 606 0 inches
E. not determined by the given information
Solution:
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Problem 28: Let g ( x ) = x 5 + x 4 + x 3 + x 2 + x + 1 g(x)=x^{5}+x^{4}+x^{3}+x^{2}+x+1g ( x ) = x 5 + x 4 + x 3 + x 2 + x + 1 . What is the remainder when the polynomial g ( x 12 ) g\left(x^{12}\right)g ( x 1 2 ) is divided by the polynomial g ( x ) ? g(x)?g ( x ) ?
Answer Choices:
A. 6 66
B. 5 β x 5-x5 β x
C. 4 β x + x 2 4-x+x^{2}4 β x + x 2
D. 3 β x + x 2 β x 3 3-x+x^{2}-x^{3}3 β x + x 2 β x 3
E. 2 β x + x 2 β x 3 + x 4 2-x+x^{2}-x^{3}+x^{4}2 β x + x 2 β x 3 + x 4
Solution:
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Problem 29: Find the smallest integer n nn such that ( x 2 + y 2 + z 2 ) 2 β©½ n ( x 4 + y 4 + z 4 ) \left(x^{2}+y^{2}+z^{2}\right)^{2} \leqslant n\left(x^{4}+y^{4}+z^{4}\right)( x 2 + y 2 + z 2 ) 2 β©½ n ( x 4 + y 4 + z 4 ) for all real numbers x , y x, yx , y and z zz .
Answer Choices:
A. 2 22
B. 3 33
C. 4 44
D. 6 66
E. There is no such integer n nn
Solution:
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Problem 30: If a , b a, ba , b and d dd are the lengths of a side, a shortest diagonal and a longest diagonal, respectively, of a regular nonagon, then
Answer Choices:
A. d = a + b d=a+bd = a + b
B. d 2 = a 2 + b 2 d^{2}=a^{2}+b^{2}d 2 = a 2 + b 2
C. d 2 = a 2 + a b + b 2 d^{2}=a^{2}+a b+b^{2}d 2 = a 2 + a b + b 2
D. b = a + d 2 b=\dfrac{a+d}{2}b = 2 a + d β
E. b 2 = a d b^{2}=a db 2 = a d
Solution:
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The problems and solutions on this page are the property of the MAA's American Mathematics Competitions